What is the integral of ((sec(x)tan(x))/(sec(x)-7)) ?

The integral of ((sec(x)tan(x))/(sec(x)-7)) is ln|sec(x)-7|+C

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integral of ((sec(x)tan(x))/(sec(x)-7))

\int (\frac{sec ( x ) tan ( x )}{sec ( x ) - 7}) d x

ln ∣ sec (x) - 7 ∣ + C

Solution steps

\int \frac{sec ( x ) tan ( x )}{sec ( x ) - 7} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = sec (x) - 7

= ln ∣ sec (x) - 7 ∣

Add a constant to the solution

= ln ∣ sec (x) - 7 ∣ + C

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\frac{\partial}{\partial y} (\frac{y}{2 x ^{2} + y ^{2}})

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What is the integral of ((sec(x)tan(x))/(sec(x)-7)) ?
The integral of ((sec(x)tan(x))/(sec(x)-7)) is ln|sec(x)-7|+C