What is the sum from n=1 to infinity of 1/(n^3+n^2) ?

The sum from n=1 to infinity of 1/(n^3+n^2) is converges

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sum from n=1 to infinity of 1/(n^3+n^2)

n = 1 \sum \infty \frac{1}{n ^{3} + n ^{2}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{3} + n ^{2}}

Apply Series Comparison Test:

converges

= converges

\frac{x ^{2} - 5 x + 3}{x ^{2} + 7}

f (x) = - 5 x^{2} + 2 x

f (x) = 5 x^{2} + 3

\frac{d}{d x} (\frac{3 sin ( x ) - 11 cos ( x )}{x - 2})

n = 1 \sum \infty \frac{n ^{n}}{5 ^{n}}

What is the sum from n=1 to infinity of 1/(n^3+n^2) ?
The sum from n=1 to infinity of 1/(n^3+n^2) is converges