What is the solution for -y^'+(3y)/x =(y^2)/x ?

The solution for -y^'+(3y)/x =(y^2)/x is y=-(3e^{3c_{1}}x^3)/(1-e^{3c_{1)}x^3}

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-y^'+(3y)/x =(y^2)/x

- y^{^{'}} + \frac{3 y}{x} = \frac{y ^{2}}{x}

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

Solution steps

- y^{'} (x) + \frac{3 y}{x} = \frac{y ^{2}}{x}

Solve separable ODE:

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

y = - \frac{3 e ^{3 c_{1}} x ^{3}}{1 - e ^{3 c_{1}} x ^{3}}

\frac{d}{d x} (\frac{7 x ^{2} + 3 x + 7}{x})

x \to 0 + lim (7 (\frac{1}{x} - cot (x)))

y^{^{''}} + 9 y = sec^{2} (3 x)

y = x^{x}

x \to + π + lim (csc (x))

What is the solution for -y^'+(3y)/x =(y^2)/x ?
The solution for -y^'+(3y)/x =(y^2)/x is y=-(3e^{3c_{1}}x^3)/(1-e^{3c_{1)}x^3}