What is the integral of x^4ln(3x) ?

The integral of x^4ln(3x) is 1/5 x^5ln(3x)-(x^5)/(25)+C

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integral of x^4ln(3x)

\int x^{4} ln (3 x) d x

\frac{1}{5} x^{5} ln (3 x) - \frac{x ^{5}}{25} + C

Solution steps

\int x^{4} ln (3 x) d x

Apply Integration By Parts

: \frac{1}{5} x^{5} ln (3 x) - \int \frac{x ^{4}}{5} d x

= \frac{1}{5} x^{5} ln (3 x) - \int \frac{x ^{4}}{5} d x

\int \frac{x ^{4}}{5} d x = \frac{x ^{5}}{25}

= \frac{1}{5} x^{5} ln (3 x) - \frac{x ^{5}}{25}

Add a constant to the solution

= \frac{1}{5} x^{5} ln (3 x) - \frac{x ^{5}}{25} + C

(x^{2} + 1)^{3} (x^{2} + 2)^{6}

\int_{- l n (4)}^{0} 33 e^{t} d t

\frac{1}{6 x ^{2} + 5}

\int 15 x^{29} cos (x^{15}) d x

\frac{d ^{2}}{d x ^{2}} (cos (3 x))

What is the integral of x^4ln(3x) ?
The integral of x^4ln(3x) is 1/5 x^5ln(3x)-(x^5)/(25)+C