What is the derivative of (sqrt(5x^4+x^2))/2 ?

The derivative of (sqrt(5x^4+x^2))/2 is (x(10x^2+1))/(2sqrt(x^2)\sqrt{5x^2+1)}

What is the first derivative of (sqrt(5x^4+x^2))/2 ?

The first derivative of (sqrt(5x^4+x^2))/2 is (x(10x^2+1))/(2sqrt(x^2)\sqrt{5x^2+1)}

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derivative of

\frac{5 x ^{4} + x ^{2}}{2}

\frac{x ( 10 x ^{2} + 1 )}{2 x ^{2} 5 x ^{2} + 1}

Solution steps

\frac{d}{d x} (\frac{5 x ^{4} + x ^{2}}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (5 x^{4} + x^{2})

Apply the chain rule:

\frac{1}{2 5 x ^{4} + x ^{2}} \frac{d}{d x} (5 x^{4} + x^{2})

= \frac{1}{2 5 x ^{4} + x ^{2}} \frac{d}{d x} (5 x^{4} + x^{2})

\frac{d}{d x} (5 x^{4} + x^{2}) = 20 x^{3} + 2 x

= \frac{1}{2} \cdot \frac{1}{2 5 x ^{4} + x ^{2}} (20 x^{3} + 2 x)

Simplify

\frac{1}{2} \cdot \frac{1}{2 5 x ^{4} + x ^{2}} (20 x^{3} + 2 x) : \frac{x ( 10 x ^{2} + 1 )}{2 x ^{2} 5 x ^{2} + 1}

= \frac{x ( 10 x ^{2} + 1 )}{2 x ^{2} 5 x ^{2} + 1}

x + 49

\frac{d}{d x} (\frac{2 x}{x ^{2} + 5})

\int \frac{1}{32768} sin (8 x) d x

3 x y^{^{'}} - 2 y = \frac{x ^{3}}{y ^{2}}

x, 2 x, - x + 2

What is the derivative of (sqrt(5x^4+x^2))/2 ?
The derivative of (sqrt(5x^4+x^2))/2 is (x(10x^2+1))/(2sqrt(x^2)\sqrt{5x^2+1)}
What is the first derivative of (sqrt(5x^4+x^2))/2 ?
The first derivative of (sqrt(5x^4+x^2))/2 is (x(10x^2+1))/(2sqrt(x^2)\sqrt{5x^2+1)}