What is the derivative of 24x^2+8x-5 ?

The derivative of 24x^2+8x-5 is 48x+8

What is the first derivative of 24x^2+8x-5 ?

The first derivative of 24x^2+8x-5 is 48x+8

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\frac{d}{d x} (24 x^{2} + 8 x - 5)

48 x + 8

Solution steps

\frac{d}{d x} (24 x^{2} + 8 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (24 x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (5)

\frac{d}{d x} (24 x^{2}) = 48 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (5) = 0

= 48 x + 8 - 0

Simplify

= 48 x + 8

\frac{d}{d t} (2 t + 3)

\int_{5}^{9} \frac{1}{x ^{2} - 1} d x

3 2 + 2 x + x^{3}

n = 3 \sum \infty \frac{3}{4} \cdot \frac{1}{4 ^{n}}

\frac{\partial}{\partial z} (x z)

What is the derivative of 24x^2+8x-5 ?
The derivative of 24x^2+8x-5 is 48x+8
What is the first derivative of 24x^2+8x-5 ?
The first derivative of 24x^2+8x-5 is 48x+8