What is the limit as x approaches 2 of sqrt(2x^2-4) ?

The limit as x approaches 2 of sqrt(2x^2-4) is 2

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limit as x approaches 2 of sqrt(2x^2-4)

x \to 2 lim (2 x^{2} - 4)

2

Solution steps

x \to 2 lim (2 x^{2} - 4)

Plug in the value

x = 2

= 2 \cdot 2^{2} - 4

Simplify

2 \cdot 2^{2} - 4 : 2

= 2

\frac{s}{( s ^{2} - 4 ) ( s + 2 )}

\frac{d}{d x} (\frac{2}{3} ln (1 + 3 cos^{2} (x)))

\int \frac{x + 3}{( 3 x - 4 ) ^{\frac{3}{2}}} d x

\frac{\partial}{\partial x} (7 x^{4} y - 7 x y^{2})

f (x) = x^{2} - 2, at x = 1

What is the limit as x approaches 2 of sqrt(2x^2-4) ?
The limit as x approaches 2 of sqrt(2x^2-4) is 2