What is the solution for y^{''}-2y^'-3y=3e^{2x} ?

The solution for y^{''}-2y^'-3y=3e^{2x} is y=c_{1}e^{3x}+c_{2}e^{-x}-e^{2x}

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y^{''}-2y^'-3y=3e^{2x}

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2 x}

y = c_{1} e^{3 x} + c_{2} e^{- x} - e^{2 x}

Solution steps

y^{''} (x) - 2 y^{'} (x) - 3 y = 3 e^{2 x}

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- x} - e^{2 x}

y = c_{1} e^{3 x} + c_{2} e^{- x} - e^{2 x}

y = x, y = 3 x, x + y = 4

n = 1 \sum \infty 0.9 9^{n}

\int sin (x + 2) d x

\int x 3 x - 2 d x

x \to 0 - lim (\frac{x ^{2}}{8} - \frac{4}{x})

What is the solution for y^{''}-2y^'-3y=3e^{2x} ?
The solution for y^{''}-2y^'-3y=3e^{2x} is y=c_{1}e^{3x}+c_{2}e^{-x}-e^{2x}