What is the sum from n=5 to infinity of (7^n)/(10^n) ?

The sum from n=5 to infinity of (7^n)/(10^n) is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=5 to infinity of (7^n)/(10^n)

n = 5 \sum \infty \frac{7 ^{n}}{1 0 ^{n}}

converges

Solution steps

n = 5 \sum \infty \frac{7 ^{n}}{1 0 ^{n}}

n \to \infty lim (n (\frac{\frac{7 ^{n}}{1 0 ^{n}}}{\frac{7 ^{n + 1}}{1 0 ^{n + 1}}} - 1)) = \infty

L > 1,

by the Raabe's test

= converges

y^{^{'}} - y = 4 t e^{2 t}, y (0) = 1

t \cdot y^{^{'}} + t \cdot y = 1 - y

\frac{\partial}{\partial x} (x e^{4 x y})

\int 8 sin^{3} (x co) s^{7} x d x

- sin (3 t)

What is the sum from n=5 to infinity of (7^n)/(10^n) ?
The sum from n=5 to infinity of (7^n)/(10^n) is converges