What is the tangent of y=x^2-2,(-2,2) ?

The tangent of y=x^2-2,(-2,2) is y=-4x-6

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tangent of y=x^2-2,(-2,2)

tangent of

y = x^{2} - 2, (- 2, 2)

y = - 4 x - 6

Solution steps

Find the slope of

y = x^{2} - 2 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(- 2, 2) : y = - 4 x - 6

y = - 4 x - 6

\frac{s ^{2} + 4}{s ^{2} + 4 s + 8}

\frac{\partial}{\partial y} (x^{2} + 3 x y)

x y^{^{''}} + 5 y^{^{'}} = x

\int \frac{1 + x ^{2}}{1 - x ^{2}} d x

\int 2 t - 3 d t

What is the tangent of y=x^2-2,(-2,2) ?
The tangent of y=x^2-2,(-2,2) is y=-4x-6