What is (\partial)/(\partial y)(x^2y+4y-7) ?

The answer to (\partial)/(\partial y)(x^2y+4y-7) is x^2+4

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(\partial)/(\partial y)(x^2y+4y-7)

\frac{\partial}{\partial y} (x^{2} y + 4 y - 7)

x^{2} + 4

Solution steps

\frac{\partial}{\partial y} (x^{2} y + 4 y - 7)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2} y) + \frac{\partial}{\partial y} (4 y) - \frac{\partial}{\partial y} (7)

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

\frac{\partial}{\partial y} (4 y) = 4

\frac{\partial}{\partial y} (7) = 0

= x^{2} + 4 - 0

Simplify

= x^{2} + 4

f (x) = (2 x - 3)^{l n (x)}

\int (x^{1.1} + 7 x^{2.5}) d x

x \to 2 lim (3 x^{3} - 1)

\frac{\partial}{\partial t} (tan (t))

(2 x) y^{^{'}} = x + 3 y

What is (\partial)/(\partial y)(x^2y+4y-7) ?
The answer to (\partial)/(\partial y)(x^2y+4y-7) is x^2+4