What is the solution for y^{''}-6y^'+9y=30t^2e^{3t} ?

The solution for y^{''}-6y^'+9y=30t^2e^{3t} is y=c_{1}e^{3t}+c_{2}te^{3t}+(5e^{3t}t^4)/2

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y^{''}-6y^'+9y=30t^2e^{3t}

y^{^{''}} - 6 y^{^{'}} + 9 y = 30 t^{2} e^{3 t}

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{5 e ^{3 t} t ^{4}}{2}

Solution steps

y^{''} (t) - 6 y^{'} (t) + 9 y = 30 t^{2} e^{3 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{5 e ^{3 t} t ^{4}}{2}

y = c_{1} e^{3 t} + c_{2} t e^{3 t} + \frac{5 e ^{3 t} t ^{4}}{2}

\frac{d}{d x} (\frac{27 x ^{3}}{8})

\frac{1}{1 + a s}

\int 8 x^{5} d x

\frac{d}{d x} (ln (x^{12}))

\frac{d}{d x} (\frac{250 x}{x + 3})

What is the solution for y^{''}-6y^'+9y=30t^2e^{3t} ?
The solution for y^{''}-6y^'+9y=30t^2e^{3t} is y=c_{1}e^{3t}+c_{2}te^{3t}+(5e^{3t}t^4)/2