What is the derivative of 2+\sqrt[5]{x} ?

The derivative of 2+\sqrt[5]{x} is 1/(5x^{4/5)}

What is the first derivative of 2+\sqrt[5]{x} ?

The first derivative of 2+\sqrt[5]{x} is 1/(5x^{4/5)}

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derivative of

2 + 5 x

\frac{1}{5 x ^{\frac{4}{5}}}

Solution steps

\frac{d}{d x} (2 + 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (5 x)

\frac{d}{d x} (2) = 0

\frac{d}{d x} (5 x) = \frac{1}{5 x ^{\frac{4}{5}}}

= 0 + \frac{1}{5 x ^{\frac{4}{5}}}

Simplify

= \frac{1}{5 x ^{\frac{4}{5}}}

\frac{\partial}{\partial x} (\frac{q ( x , r , s , t ) x + r}{s x + t})

\frac{d}{d x} (sinh (cosh (x)))

\frac{d}{d x} (x - \frac{2}{x})

f (x) = x^{3} - 6 x, (2, - 4)

\int_{- 1}^{3} (2 x^{2} + 1) d x

What is the derivative of 2+\sqrt[5]{x} ?
The derivative of 2+\sqrt[5]{x} is 1/(5x^{4/5)}
What is the first derivative of 2+\sqrt[5]{x} ?
The first derivative of 2+\sqrt[5]{x} is 1/(5x^{4/5)}