What is the integral of (1-x)/(3e^x) ?

The integral of (1-x)/(3e^x) is x/(3e^x)+C

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integral of (1-x)/(3e^x)

\int \frac{1 - x}{3 e ^{x}} d x

\frac{x}{3 e ^{x}} + C

Solution steps

\int \frac{1 - x}{3 e ^{x}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int \frac{1 - x}{e ^{x}} d x

Apply u-substitution

: \int \frac{1 - ln ( u )}{u ^{2}} d u

= \frac{1}{3} \cdot \int \frac{1 - ln ( u )}{u ^{2}} d u

Apply Integration By Parts

: - \frac{1 - ln ( u )}{u} - \int \frac{1}{u ^{2}} d u

= \frac{1}{3} (- \frac{1 - ln ( u )}{u} - \int \frac{1}{u ^{2}} d u)

\int \frac{1}{u ^{2}} d u = - \frac{1}{u}

= \frac{1}{3} (- \frac{1 - ln ( u )}{u} - (- \frac{1}{u}))

Substitute back

u = e^{x}

= \frac{1}{3} (- \frac{1 - ln ( e ^{x} )}{e ^{x}} - (- \frac{1}{e ^{x}}))

Simplify

\frac{1}{3} (- \frac{1 - ln ( e ^{x} )}{e ^{x}} - (- \frac{1}{e ^{x}})) : \frac{x}{3 e ^{x}}

= \frac{x}{3 e ^{x}}

Add a constant to the solution

= \frac{x}{3 e ^{x}} + C

x \to 3 lim (x^{2} - 4)

x \to 0 lim (\frac{( 1 + x ) ^{3} - 1}{x})

\frac{d}{d x} (sin (\frac{π}{x}))

x \to 0 lim (\frac{1}{sin ( x ^{2} )})

\int \frac{5}{x ( x ^{4} + 1 )} d x

What is the integral of (1-x)/(3e^x) ?
The integral of (1-x)/(3e^x) is x/(3e^x)+C