What is the derivative of y= 1/(sin(x)) ?

The derivative of y= 1/(sin(x)) is -cot(x)csc(x)

What is the first derivative of y= 1/(sin(x)) ?

The first derivative of y= 1/(sin(x)) is -cot(x)csc(x)

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derivative of

y = \frac{1}{sin ( x )}

- cot (x) csc (x)

Solution steps

\frac{d}{d x} (\frac{1}{sin ( x )})

Simplify

\frac{1}{sin ( x )} : csc (x)

= \frac{d}{d x} (csc (x))

Apply the common derivative:

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

= - cot (x) csc (x)

\frac{d ^{3}}{d x ^{3}} (\frac{3}{x ^{2}})

30

\frac{d}{d x} (\frac{7}{4 x})

\frac{d}{d x} (\frac{8}{x + 2})

\frac{\partial}{\partial x} (y^{2} - x^{2} - 8)

What is the derivative of y= 1/(sin(x)) ?
The derivative of y= 1/(sin(x)) is -cot(x)csc(x)
What is the first derivative of y= 1/(sin(x)) ?
The first derivative of y= 1/(sin(x)) is -cot(x)csc(x)