What is inverse oflaplace 3/(s^2) ?

The answer to inverse oflaplace 3/(s^2) is 3t

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inverse oflaplace 3/(s^2)

inverse laplace

\frac{3}{s ^{2}}

3 t

Solution steps

L^{- 1} {\frac{3}{s ^{2}}}

= L^{- 1} {3 \cdot \frac{1}{s ^{2}}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 3 L^{- 1} {\frac{1}{s ^{2}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{1}{s ^{2}}} = t

= 3 t

\int \frac{1}{cos ( 4 x )} d x

x \to 4 lim (\frac{- 6}{4 - x})

\int x^{3} x^{2} + 41 d x

y = \frac{10}{( 10 - x ^{4} ) ^{\frac{3}{2}}}

\int \frac{x ^{2} + x - 6}{x ^{2} - 9} d x

What is inverse oflaplace 3/(s^2) ?
The answer to inverse oflaplace 3/(s^2) is 3t