What is the derivative of (4x-1^3) ?

The derivative of (4x-1^3) is 12(4x-1)^2

What is the first derivative of (4x-1^3) ?

The first derivative of (4x-1^3) is 12(4x-1)^2

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\frac{d}{d x} ((4 x - 1)^{3})

12 (4 x - 1)^{2}

Solution steps

\frac{d}{d x} ((4 x - 1)^{3})

Apply the chain rule:

3 (4 x - 1)^{2} \frac{d}{d x} (4 x - 1)

= 3 (4 x - 1)^{2} \frac{d}{d x} (4 x - 1)

\frac{d}{d x} (4 x - 1) = 4

= 3 (4 x - 1)^{2} \cdot 4

Simplify

= 12 (4 x - 1)^{2}

\int \frac{5 x}{2 x ^{3} + 6 x ^{2}} d x

\int \frac{x}{( 5 - x ^{2} ) ^{7}} d x

f (t) = sec^{2} (2 t)

y^{^{''}} + 3 y^{^{'}} - 4 y = 10 e^{x} - 250 cos (3 x)

n = 1 \sum \infty \frac{4 ^{n}}{n ^{4}}

What is the derivative of (4x-1^3) ?
The derivative of (4x-1^3) is 12(4x-1)^2
What is the first derivative of (4x-1^3) ?
The first derivative of (4x-1^3) is 12(4x-1)^2