What is the solution for (dx)/(dt)=-3x(1/10 e^{-2t}),x(0)= 4/5 ?

The solution for (dx)/(dt)=-3x(1/10 e^{-2t}),x(0)= 4/5 is x=(4e^{(3e^{-2t}-3)/(20)})/5

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(dx)/(dt)=-3x(1/10 e^{-2t}),x(0)= 4/5

\frac{d x}{d t} = - 3 x (\frac{1}{10} e^{- 2 t}), x (0) = \frac{4}{5}

x = \frac{4 e ^{\frac{3 e ^{- 2 t} - 3}{20}}}{5}

Solution steps

\frac{d x}{d t} = - 3 x (\frac{1}{10} e^{- 2 t})

Solve separable ODE:

x = \frac{4 e ^{\frac{3 e ^{- 2 t} - 3}{20}}}{5}

x = \frac{4 e ^{\frac{3 e ^{- 2 t} - 3}{20}}}{5}

\frac{\partial}{\partial y} (- 3 x^{2} + 7 x y - 4 y^{2} + x + y)

x y^{2} y^{^{'}} = y^{3} - 5 x^{3}, y (1) = 6

\int \frac{1}{2} e^{2 t} d t

\frac{\partial}{\partial z} (5 x^{\frac{y}{z}})

\int 3 cos^{2} (x t a) n^{3} x d x

What is the solution for (dx)/(dt)=-3x(1/10 e^{-2t}),x(0)= 4/5 ?
The solution for (dx)/(dt)=-3x(1/10 e^{-2t}),x(0)= 4/5 is x=(4e^{(3e^{-2t}-3)/(20)})/5