What is the solution for (dy}{dt}=\frac{3y)/t+t^5 ?

The solution for (dy}{dt}=\frac{3y)/t+t^5 is y=(t^6)/3+c_{1}t^3

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(dy}{dt}=\frac{3y)/t+t^5

\frac{d y}{d t} = \frac{3 y}{t} + t^{5}

y = \frac{t ^{6}}{3} + c_{1} t^{3}

Solution steps

\frac{d y}{d t} = \frac{3 y}{t} + t^{5}

Solve linear ODE:

y = \frac{t ^{6}}{3} + c_{1} t^{3}

y = \frac{t ^{6}}{3} + c_{1} t^{3}

x \to c lim (f (x))

\frac{d}{d x} (- 2 \cdot x \cdot e^{- x^{2}})

\int \frac{1}{x 196 x ^{2} - 196} d x

\frac{x ^{2}}{5 + 4 x}

e^{x}, e^{- 3 x}, ln (4)

What is the solution for (dy}{dt}=\frac{3y)/t+t^5 ?
The solution for (dy}{dt}=\frac{3y)/t+t^5 is y=(t^6)/3+c_{1}t^3