What is the integral of e^{2x}sin(7x) ?

The integral of e^{2x}sin(7x) is -(7e^{2x}cos(7x))/(53)+(2e^{2x}sin(7x))/(53)+C

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integral of e^{2x}sin(7x)

\int e^{2 x} sin (7 x) d x

- \frac{7 e ^{2 x} cos ( 7 x )}{53} + \frac{2 e ^{2 x} sin ( 7 x )}{53} + C

Solution steps

\int e^{2 x} sin (7 x) d x

Apply Integration By Parts

: - \frac{1}{7} e^{2 x} cos (7 x) - \int - \frac{2}{7} e^{2 x} cos (7 x) d x

= - \frac{1}{7} e^{2 x} cos (7 x) - \int - \frac{2}{7} e^{2 x} cos (7 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{7} e^{2 x} cos (7 x) - (- \frac{2}{7} \cdot \int e^{2 x} cos (7 x) d x)

Apply Integration By Parts

: \frac{1}{7} e^{2 x} sin (7 x) - \int \frac{2}{7} e^{2 x} sin (7 x) d x

= - \frac{1}{7} e^{2 x} cos (7 x) - (- \frac{2}{7} (\frac{1}{7} e^{2 x} sin (7 x) - \int \frac{2}{7} e^{2 x} sin (7 x) d x))

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{7} e^{2 x} cos (7 x) - (- \frac{2}{7} (\frac{1}{7} e^{2 x} sin (7 x) - \frac{2}{7} \cdot \int e^{2 x} sin (7 x) d x))

Therefore

\int e^{2 x} sin (7 x) d x = - \frac{1}{7} e^{2 x} cos (7 x) - (- \frac{2}{7} (\frac{1}{7} e^{2 x} sin (7 x) - \frac{2}{7} \cdot \int e^{2 x} sin (7 x) d x))

Isolate

\int e^{2 x} sin (7 x) d x

= - \frac{7 e ^{2 x} cos ( 7 x )}{53} + \frac{2 e ^{2 x} sin ( 7 x )}{53}

Add a constant to the solution

= - \frac{7 e ^{2 x} cos ( 7 x )}{53} + \frac{2 e ^{2 x} sin ( 7 x )}{53} + C

e^{- a s}

y = 2 x^{4} - 16 x^{2} + 9, at

\int \frac{x}{3 e ^{2 x}} d x

x \cdot \frac{d y}{d x} - y = 5 x^{2}

h \to 0 lim (2 h)

What is the integral of e^{2x}sin(7x) ?
The integral of e^{2x}sin(7x) is -(7e^{2x}cos(7x))/(53)+(2e^{2x}sin(7x))/(53)+C