What is the solution for (y+sqrt(x^2+y^2))dx-xdy=0 ?

The solution for (y+sqrt(x^2+y^2))dx-xdy=0 is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2

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(y+sqrt(x^2+y^2))dx-xdy=0

(y + x^{2} + y^{2}) d x - x d y = 0

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

Solution steps

(y + x^{2} + y^{2}) d x - x d y = 0

Solve using substitution:

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

y = - \frac{1}{2 e ^{c_{1}}} + \frac{e ^{c_{1}} x ^{2}}{2}

f (x) = e^{x} - 4 x^{3}

x \to - 6 lim (2 x + 1)

e^{2 x}

\int_{1}^{4} 9 \frac{ln ( x )}{x ^{2}} d x

\frac{- 2}{s + 3}

What is the solution for (y+sqrt(x^2+y^2))dx-xdy=0 ?
The solution for (y+sqrt(x^2+y^2))dx-xdy=0 is y=-1/(2e^{c_{1)}}+(e^{c_{1}}x^2)/2