What is (\partial)/(\partial y)(6xy^2+x^2) ?

The answer to (\partial)/(\partial y)(6xy^2+x^2) is 12xy

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(\partial)/(\partial y)(6xy^2+x^2)

\frac{\partial}{\partial y} (6 x y^{2} + x^{2})

12 x y

Solution steps

\frac{\partial}{\partial y} (6 x y^{2} + x^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (6 x y^{2}) + \frac{\partial}{\partial y} (x^{2})

\frac{\partial}{\partial y} (6 x y^{2}) = 12 x y

\frac{\partial}{\partial y} (x^{2}) = 0

= 12 x y + 0

Simplify

= 12 x y

x \to 5 - lim (\frac{- 2}{x ^{2} - 25})

\int sin (2 x + y) - sin (x + y) d x

f (x) = x^{\frac{6}{5}}

y^{^{''}} - y^{^{'}} + 2 y = 0

\frac{\partial}{\partial x} (e^{y} + x + x^{3} + 5)

What is (\partial)/(\partial y)(6xy^2+x^2) ?
The answer to (\partial)/(\partial y)(6xy^2+x^2) is 12xy