What is the limit as n approaches infinity of 1/(2n) ?

The limit as n approaches infinity of 1/(2n) is 0

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limit as n approaches infinity of 1/(2n)

n \to \infty lim (\frac{1}{2 n})

0

Solution steps

n \to \infty lim (\frac{1}{2 n})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= \frac{1}{2} \cdot n \to \infty lim (\frac{1}{n})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= \frac{1}{2} \cdot \frac{lim _{n \to \infty} ( 1 )}{lim _{n \to \infty} ( n )}

n \to \infty lim (1) = 1

n \to \infty lim (n) = \infty

= \frac{1}{2} \cdot \frac{1}{\infty}

Simplify

\frac{1}{2} \cdot \frac{1}{\infty} : 0

= 0

\int \frac{x ^{2}}{2 x + 1} d x

\frac{d}{d x} (5 x cos (\frac{x}{5}))

x x + 3

\int_{6}^{7} \frac{x}{x ^{2} + 6 x + 13} d x

y^{^{''}} + \frac{1}{2} y^{^{'}} + y = 0

What is the limit as n approaches infinity of 1/(2n) ?
The limit as n approaches infinity of 1/(2n) is 0