What is the solution for y^'=100ky-ky^2 ?

The solution for y^'=100ky-ky^2 is y=-(100e^{100kt+100c_{1}})/(1-e^{100(kt+c_{1))}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=100ky-ky^2

y^{^{'}} = 100 k y - k y^{2}

y = - \frac{100 e ^{100 k t + 100 c_{1}}}{1 - e ^{100 (k t + c_{1})}}

Solution steps

y^{'} (t) = 100 k y (t) - k y (t)^{2}

Solve separable ODE:

y = - \frac{100 e ^{100 k t + 100 c_{1}}}{1 - e ^{100 (k t + c_{1})}}

y = - \frac{100 e ^{100 k t + 100 c_{1}}}{1 - e ^{100 (k t + c_{1})}}

\int \frac{1}{x - 25} d x

\int \frac{5 x ^{2} + 7 x + 2}{( x ^{2} + 2 ) ( x + 4 )} d x

\int 2 e^{\frac{r}{2}} d r

\frac{\partial}{\partial x} (3 x x^{2} + y^{2})

\frac{\partial}{\partial x} (2 y x^{2} - cos (y))

What is the solution for y^'=100ky-ky^2 ?
The solution for y^'=100ky-ky^2 is y=-(100e^{100kt+100c_{1}})/(1-e^{100(kt+c_{1))}}