en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=-0.02y-4

Solution

y^{^{'}} = - 0.02 y - 4

Solution

y = 50 e^{\frac{- t - c _{1}}{50}} - 200

Solution steps

y^{'} (t) = - 0.02 y - 4

Solve separable ODE:

y = 50 e^{\frac{- t - c _{1}}{50}} - 200

y = 50 e^{\frac{- t - c _{1}}{50}} - 200

Graph

Popular Examples

integral of-cos((nxpi)/2)

\int - cos (\frac{n x π}{2}) d x

derivative of (4-t)(2+t^2)^{-1}derivative of

(4 - t) (2 + t^{2})^{- 1}

x y^{^{'}} + y = x^{2} y^{2}

integral of (x+5)/(\sqrt[3]{x+9)}

\int \frac{x + 5}{3 x + 9} d x

integral of 1/2 (1-cos(θ))^2

\int \frac{1}{2} (1 - cos (θ))^{2} d θ

Frequently Asked Questions (FAQ)

What is the solution for y^'=-0.02y-4 ?
The solution for y^'=-0.02y-4 is y=50e^{(-t-c_{1})/(50)}-200