What is the tangent of y=sin(x),\at x=(7pi)/6 ?

The tangent of y=sin(x),\at x=(7pi)/6 is y=-(sqrt(3))/2 x-1/2+(7pi)/(4sqrt(3))

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tangent of y=sin(x),\at x=(7pi)/6

tangent of

y = sin (x), at x = \frac{7 π}{6}

y = - \frac{3}{2} x - \frac{1}{2} + \frac{7 π}{4 3}

Solution steps

Find the tangent point:

(\frac{7 π}{6}, - \frac{1}{2})

Find the slope of

y = sin (x) : \frac{d y}{d x} = cos (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{2}

Find the line with slope m=

- \frac{3}{2}

and passing through

(\frac{7 π}{6}, - \frac{1}{2}) : y = - \frac{3}{2} x - \frac{1}{2} + \frac{7 π}{4 3}

y = - \frac{3}{2} x - \frac{1}{2} + \frac{7 π}{4 3}

x \to 0.9 lim (2 x^{2} - 5 x + 1)

\int - \frac{x}{x + 1} d x

f (x) = \frac{1}{x ^{6}}, (- 2, \frac{1}{64})

\int_{0}^{1} \frac{4}{x ^{2} + 3 x + 2} d x

\frac{d}{d x} (x^{\frac{2}{5}} (x - 5))

What is the tangent of y=sin(x),\at x=(7pi)/6 ?
The tangent of y=sin(x),\at x=(7pi)/6 is y=-(sqrt(3))/2 x-1/2+(7pi)/(4sqrt(3))