What is taylor 1/(1-x),7 ?

The answer to taylor 1/(1-x),7 is -1/6+1/36 (x-7)-1/216 (x-7)^2+1/1296 (x-7)^3-1/7776 (x-7)^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor 1/(1-x),7

taylor

\frac{1}{1 - x}, 7

- \frac{1}{6} + \frac{1}{36} (x - 7) - \frac{1}{216} (x - 7)^{2} + \frac{1}{1296} (x - 7)^{3} - \frac{1}{7776} (x - 7)^{4} + \dots

Solution steps

Apply the Taylor Formula

= - \frac{1}{6} + \frac{\frac{d}{d x} ( \frac{1}{1 - x} ) ( 7 )}{1 !} (x - 7) + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{1}{1 - x} ) ( 7 )}{2 !} (x - 7)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{1}{1 - x} ) ( 7 )}{3 !} (x - 7)^{3} + \dots

Evaluate Derivatives

= - \frac{1}{6} + \frac{\frac{1}{36}}{1 !} (x - 7) + \frac{- \frac{1}{108}}{2 !} (x - 7)^{2} + \frac{\frac{1}{216}}{3 !} (x - 7)^{3} + \frac{- \frac{1}{324}}{4 !} (x - 7)^{4} + \dots

Refine

= - \frac{1}{6} + \frac{1}{36} (x - 7) - \frac{1}{216} (x - 7)^{2} + \frac{1}{1296} (x - 7)^{3} - \frac{1}{7776} (x - 7)^{4} + \dots

\int (x^{7} - 5 x^{- 2} + 4) d x

\frac{d}{d x} (x cos (\frac{π}{5}))

\frac{d}{d x} (x e n (x))

x \to 0 lim (\frac{8 x}{sin ( x )})

\frac{\partial}{\partial x} (7 x - 5 x^{2} y + 8 y z^{2})

What is taylor 1/(1-x),7 ?
The answer to taylor 1/(1-x),7 is -1/6+1/36 (x-7)-1/216 (x-7)^2+1/1296 (x-7)^3-1/7776 (x-7)^4+\ldots