What is area f(x)=x^2-6x+8,g(x)=-2x+8 ?

The answer to area f(x)=x^2-6x+8,g(x)=-2x+8 is 32/3

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area f(x)=x^2-6x+8,g(x)=-2x+8

area

f (x) = x^{2} - 6 x + 8, g (x) = - 2 x + 8

\frac{32}{3}

Decimal

10.66666 \dots

Solution steps

Apply the area formula:

\int_{0}^{4} x^{2} - 6 x + 8 - (- 2 x + 8) d x

Solve

\int_{0}^{4} x^{2} - 6 x + 8 - (- 2 x + 8) d x : \frac{32}{3}

The area is:

= \frac{32}{3}

y^{^{''}} + 8 y^{^{'}} + 16 = 0

w^{\frac{3}{2}} (w + c e^{w})

\frac{d}{d x} (ln (x^{3} + 3))

x \to 0 lim (\frac{x}{x - 1})

x \to 0 lim (x - 4)

What is area f(x)=x^2-6x+8,g(x)=-2x+8 ?
The answer to area f(x)=x^2-6x+8,g(x)=-2x+8 is 32/3