What is the integral of (3x^2+2x-3)/(x^3-x) ?

The integral of (3x^2+2x-3)/(x^3-x) is 3ln|x|-ln|x+1|+ln|x-1|+C

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integral of (3x^2+2x-3)/(x^3-x)

\int \frac{3 x ^{2} + 2 x - 3}{x ^{3} - x} d x

3 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + C

Solution steps

\int \frac{3 x ^{2} + 2 x - 3}{x ^{3} - x} d x

Take the partial fraction of

\frac{3 x ^{2} + 2 x - 3}{x ^{3} - x} : \frac{3}{x} - \frac{1}{x + 1} + \frac{1}{x - 1}

= \int \frac{3}{x} - \frac{1}{x + 1} + \frac{1}{x - 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{x} d x - \int \frac{1}{x + 1} d x + \int \frac{1}{x - 1} d x

\int \frac{3}{x} d x = 3 ln ∣ x ∣

\int \frac{1}{x + 1} d x = ln ∣ x + 1 ∣

\int \frac{1}{x - 1} d x = ln ∣ x - 1 ∣

= 3 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣

Add a constant to the solution

= 3 ln ∣ x ∣ - ln ∣ x + 1 ∣ + ln ∣ x - 1 ∣ + C

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\int \frac{5}{( x + 2 ) ^{2}} d x

\int \frac{1}{x ^{2} - 81} d x

f (x) = sin (2 x) cos (3 x)

\int 3 sin (5 x + 4) d x

What is the integral of (3x^2+2x-3)/(x^3-x) ?
The integral of (3x^2+2x-3)/(x^3-x) is 3ln|x|-ln|x+1|+ln|x-1|+C