What is the solution for y^{''}-y=0,y(0)=0,y(1)=1 ?

The solution for y^{''}-y=0,y(0)=0,y(1)=1 is y=-e/(-e^2+1)e^t+e/(-e^2+1)e^{-t}

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y^{''}-y=0,y(0)=0,y(1)=1

y^{^{''}} - y = 0, y (0) = 0, y (1) = 1

y = - \frac{e}{- e ^{2} + 1} e^{t} + \frac{e}{- e ^{2} + 1} e^{- t}

Solution steps

y^{''} (t) - y = 0

Solve linear ODE:

y = - \frac{e}{- e ^{2} + 1} e^{t} + \frac{e}{- e ^{2} + 1} e^{- t}

y = - \frac{e}{- e ^{2} + 1} e^{t} + \frac{e}{- e ^{2} + 1} e^{- t}

\int \frac{e ^{\frac{1}{x}}}{x ^{3}} d x

x \to - 1 lim (- 12 x^{3})

y^{^{''}} + 2 y^{^{'}} = 0, y (0) = 1, y^{^{'}} (0) = 1

x \to 1 - lim (\frac{x ^{n}}{x - n})

\frac{d}{d x} (ln ∣ e^{x y} cos (x) ∣)

What is the solution for y^{''}-y=0,y(0)=0,y(1)=1 ?
The solution for y^{''}-y=0,y(0)=0,y(1)=1 is y=-e/(-e^2+1)e^t+e/(-e^2+1)e^{-t}