What is the tangent of sqrt(7x+2),\at x=2 ?

The tangent of sqrt(7x+2),\at x=2 is y= 7/8 x+9/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of sqrt(7x+2),\at x=2

tangent of

7 x + 2, at x = 2

y = \frac{7}{8} x + \frac{9}{4}

Solution steps

Find the tangent point:

(2, 4)

Find the slope of

y = 7 x + 2 : \frac{d y}{d x} = \frac{7}{2 7 x + 2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{8}

Find the line with slope m=

\frac{7}{8}

and passing through

(2, 4) : y = \frac{7}{8} x + \frac{9}{4}

y = \frac{7}{8} x + \frac{9}{4}

5^{3 x}

\frac{d}{d x} ((x + 1)^{2} (x^{2} + 1)^{- 3})

\frac{\partial}{\partial x} (e^{x^{2} + y^{2}} \cdot 2 x)

\int \frac{2 y}{1 + y ^{2}} d y

\int tanh (2 x) ln (cosh (2 x)) d x

What is the tangent of sqrt(7x+2),\at x=2 ?
The tangent of sqrt(7x+2),\at x=2 is y= 7/8 x+9/4