What is laplacetransform 2e^{-5t}sin(2t) ?

The answer to laplacetransform 2e^{-5t}sin(2t) is 4/((s+5)^2+4)

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laplacetransform 2e^{-5t}sin(2t)

laplace transform

2 e^{- 5 t} sin (2 t)

\frac{4}{( s + 5 ) ^{2} + 4}

Solution steps

L {2 e^{- 5 t} sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 2 L {e^{- 5 t} sin (2 t)}

L {e^{- 5 t} sin (2 t)} : \frac{2}{( s + 5 ) ^{2} + 4}

= 2 \cdot \frac{2}{( s + 5 ) ^{2} + 4}

Refine

2 \frac{2}{( s + 5 ) ^{2} + 4} : \frac{4}{( s + 5 ) ^{2} + 4}

= \frac{4}{( s + 5 ) ^{2} + 4}

y^{^{'}} = 3 3 y^{2}

f (x) = x ln (x^{2})

(- 2, - 4), (- 3, - 3)

\frac{\partial}{\partial x} (e^{x y} y)

\frac{d}{d x} ((x + \frac{1}{x})^{2})

What is laplacetransform 2e^{-5t}sin(2t) ?
The answer to laplacetransform 2e^{-5t}sin(2t) is 4/((s+5)^2+4)