What is the tangent of f(x)=3x^2,\at x=4 ?

The tangent of f(x)=3x^2,\at x=4 is y=24x-48

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tangent of f(x)=3x^2,\at x=4

tangent of

f (x) = 3 x^{2}, at x = 4

y = 24 x - 48

Solution steps

Find the tangent point:

(4, 48)

Find the slope of

f (x) = 3 x^{2} : \frac{df ( x )}{d x} = 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 24

Find the line with slope m=

24

and passing through

(4, 48) : y = 24 x - 48

y = 24 x - 48

\frac{d}{d x} (\frac{x + 5}{x})

x^{2} y^{^{''}} + x y^{^{'}} - y = x^{\frac{1}{2}}

x \to \infty lim (\frac{4 ^{x} + 3}{4 ^{x + 1}})

f (x) = - \frac{2}{x}

\int (csc (x)) d x

What is the tangent of f(x)=3x^2,\at x=4 ?
The tangent of f(x)=3x^2,\at x=4 is y=24x-48