What is (\partial)/(\partial x)(x^{yz}) ?

The answer to (\partial)/(\partial x)(x^{yz}) is yzx^{yz-1}

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(\partial)/(\partial x)(x^{yz})

\frac{\partial}{\partial x} (x^{yz})

yz x^{yz - 1}

Solution steps

\frac{\partial}{\partial x} (x^{yz})

Treat

y, z

as constants

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= yz x^{yz - 1}

\frac{d}{d x} (\frac{- 6}{x ^{4}})

\frac{d}{d x} (x^{4} tan (x) - x)

\frac{d}{d x} (\frac{( e ^{2 x} )}{2})

y = x^{9} e^{x}

\int 12 (e^{0.02 x} - 1) d x

What is (\partial)/(\partial x)(x^{yz}) ?
The answer to (\partial)/(\partial x)(x^{yz}) is yzx^{yz-1}