What is the derivative of 2x^{-5} ?

The derivative of 2x^{-5} is -(10)/(x^6)

What is the first derivative of 2x^{-5} ?

The first derivative of 2x^{-5} is -(10)/(x^6)

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derivative of

2 x^{- 5}

- \frac{10}{x ^{6}}

Solution steps

\frac{d}{d x} (2 x^{- 5})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{- 5})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 (- 5 x^{- 5 - 1})

Simplify

2 (- 5 x^{- 5 - 1}) : - \frac{10}{x ^{6}}

= - \frac{10}{x ^{6}}

\int - 2 cos (x) d x

\int_{1}^{6} x - 1 d x

y = (13 x^{2} - 26 x + 26) e^{- 8 x}

\int 36 - x^{2} d x

\frac{d}{d x} (\frac{( x + 2 )}{2 - x})

What is the derivative of 2x^{-5} ?
The derivative of 2x^{-5} is -(10)/(x^6)
What is the first derivative of 2x^{-5} ?
The first derivative of 2x^{-5} is -(10)/(x^6)