What is (\partial)/(\partial y)(2x-4y) ?

The answer to (\partial)/(\partial y)(2x-4y) is -4

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(\partial)/(\partial y)(2x-4y)

\frac{\partial}{\partial y} (2 x - 4 y)

- 4

Solution steps

\frac{\partial}{\partial y} (2 x - 4 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) - \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (4 y) = 4

= 0 - 4

Simplify

= - 4

\int \frac{4 x ^{2} + 3}{0.4 x ^{3} + 0.9 x} d x

\frac{d}{d t} (\frac{t ^{3} - 2 t ^{2} + 2 t - 4}{t ^{2} + 2})

sin (θ)

\int \frac{1}{x ^{2} - 10 x} d x

y^{^{'}} = y^{2} + 3

What is (\partial)/(\partial y)(2x-4y) ?
The answer to (\partial)/(\partial y)(2x-4y) is -4