What is the integral from 5 to 5.89 of 0.75(y-5)^2+5 ?

The integral from 5 to 5.89 of 0.75(y-5)^2+5 is 4.62624225

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integral from 5 to 5.89 of 0.75(y-5)^2+5

\int_{5}^{5.89} 0.75 (y - 5)^{2} + 5 d y

4.62624225

Solution steps

\int_{5}^{5.89} 0.75 (y - 5)^{2} + 5 d y

Simplify

0.75 (y - 5)^{2} + 5 : 0.75 y^{2} - 7.5 y + 23.75

= \int_{5}^{5.89} 0.75 y^{2} - 7.5 y + 23.75 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{5}^{5.89} 0.75 y^{2} d y - \int_{5}^{5.89} 7.5 y d y + \int_{5}^{5.89} 23.75 d y

\int_{5}^{5.89} 0.75 y^{2} d y = 19.83411 \dots

\int_{5}^{5.89} 7.5 y d y = 36.345375

\int_{5}^{5.89} 23.75 d y = 21.1375

= 19.83411 \dots - 36.345375 + 21.1375

Simplify

= 4.62624225

\frac{d}{d x} (- x e^{- 2 x y})

0.01 (0.2 t^{2} + 4 t + 64)^{\frac{2}{3}}

x \to 2 lim (3 x + 1)

\int \frac{x - 1}{2 x - x + 1} d x

\frac{d}{d x} (2 x e^{- 2 x})

What is the integral from 5 to 5.89 of 0.75(y-5)^2+5 ?
The integral from 5 to 5.89 of 0.75(y-5)^2+5 is 4.62624225