What is the derivative of 5/(4x^3+4) ?

The derivative of 5/(4x^3+4) is -(15x^2)/(4(x^3+1)^2)

What is the first derivative of 5/(4x^3+4) ?

The first derivative of 5/(4x^3+4) is -(15x^2)/(4(x^3+1)^2)

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Popular >

\frac{d}{d x} (\frac{5}{4 x ^{3} + 4})

- \frac{15 x ^{2}}{4 ( x ^{3} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{5}{4 x ^{3} + 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d x} (\frac{1}{4 x ^{3} + 4})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 5 \frac{d}{d x} ((4 x^{3} + 4)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 x ^{3} + 4 ) ^{2}} \frac{d}{d x} (4 x^{3} + 4)

= - \frac{1}{( 4 x ^{3} + 4 ) ^{2}} \frac{d}{d x} (4 x^{3} + 4)

\frac{d}{d x} (4 x^{3} + 4) = 12 x^{2}

= 5 (- \frac{1}{( 4 x ^{3} + 4 ) ^{2}} \cdot 12 x^{2})

Simplify

5 (- \frac{1}{( 4 x ^{3} + 4 ) ^{2}} \cdot 12 x^{2}) : - \frac{15 x ^{2}}{4 ( x ^{3} + 1 ) ^{2}}

= - \frac{15 x ^{2}}{4 ( x ^{3} + 1 ) ^{2}}

\int 28 (7 x - 2)^{- 5} d x

\frac{\partial}{\partial x} (\frac{( 2 x - 2 y )}{4 x + 2 y})

\frac{\partial}{\partial x} (t^{2} e^{\frac{x ^{2}}{2 t}})

- x, - 10 x + 14, x = 0

x^{3} e^{2 x}

What is the derivative of 5/(4x^3+4) ?
The derivative of 5/(4x^3+4) is -(15x^2)/(4(x^3+1)^2)
What is the first derivative of 5/(4x^3+4) ?
The first derivative of 5/(4x^3+4) is -(15x^2)/(4(x^3+1)^2)