What is the integral of sec^2(x)tan^{10}(x) ?

The integral of sec^2(x)tan^{10}(x) is (tan^{11}(x))/(11)+C

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integral of sec^2(x)tan^{10}(x)

\int sec^{2} (x) tan^{10} (x) d x

\frac{tan ^{11} ( x )}{11} + C

Solution steps

\int sec^{2} (x) tan^{10} (x) d x

Rewrite using trig identities

= \int (1 + tan^{2} (x)) tan^{10} (x) d x

Apply u-substitution

: \int u^{10} d u

= \int u^{10} d u

Apply the Power Rule

: \frac{u ^{11}}{11}

= \frac{u ^{11}}{11}

Substitute back

u = tan (x)

= \frac{tan ^{11} ( x )}{11}

Add a constant to the solution

= \frac{tan ^{11} ( x )}{11} + C

e^{(x + 1)}

x + \frac{36}{x}

y = x^{4} e^{x}

x \to 5 lim (6)

x^{^{''}} + 2 x^{^{'}} + 4 x = 0

What is the integral of sec^2(x)tan^{10}(x) ?
The integral of sec^2(x)tan^{10}(x) is (tan^{11}(x))/(11)+C