What is the solution for y^{''}-4y^'+21y=0 ?

The solution for y^{''}-4y^'+21y=0 is y=e^{2t}(c_{1}cos(sqrt(17)t)+c_{2}sin(sqrt(17)t))

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y^{''}-4y^'+21y=0

y^{^{''}} - 4 y^{^{'}} + 21 y = 0

y = e^{2 t} (c_{1} cos (17 t) + c_{2} sin (17 t))

Solution steps

y^{''} (t) - 4 y^{'} (t) + 21 y = 0

Solve linear ODE:

y = e^{2 t} (c_{1} cos (17 t) + c_{2} sin (17 t))

y = e^{2 t} (c_{1} cos (17 t) + c_{2} sin (17 t))

\int (x^{2} + sin (x)) d x

\frac{d}{d x} (a^{2} - x^{2})

y = 5 x + 2

k = 3 \sum \infty \frac{3}{k ^{2} - 2 k}

(5 x + 7)^{2}

What is the solution for y^{''}-4y^'+21y=0 ?
The solution for y^{''}-4y^'+21y=0 is y=e^{2t}(c_{1}cos(sqrt(17)t)+c_{2}sin(sqrt(17)t))