What is the integral from 0 to 3.5 of 90x ?

The integral from 0 to 3.5 of 90x is 551.25

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integral from 0 to 3.5 of 90x

\int_{0}^{3.5} 90 x d x

551.25

Solution steps

\int_{0}^{3.5} 90 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 90 \cdot \int_{0}^{3.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{3.5}

= 90 [\frac{x ^{2}}{2}]_{0}^{3.5}

Simplify

= 90 [0.5 x^{2}]_{0}^{3.5}

Compute the boundaries:

6.125

= 90 \cdot 6.125

Simplify

= 551.25

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\frac{d}{d x} (5 + 6 x^{\frac{3}{2}})

What is the integral from 0 to 3.5 of 90x ?
The integral from 0 to 3.5 of 90x is 551.25