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Popular >

(x+2/y)dy+ydx=0

Solution

(x + \frac{2}{y}) d y + y d x = 0

Solution

y = \frac{2 W ( \frac{x c _{1}}{2} )}{x}

Solution steps

(x + \frac{2}{y}) d y + y d x = 0

Solve exact ODE:

y = \frac{2 W ( \frac{x c _{1}}{2} )}{x}

y = \frac{2 W ( \frac{x c _{1}}{2} )}{x}

Popular Examples

integral from 0 to 2 of 1/(x^3)

\int_{0}^{2} \frac{1}{x ^{3}} d x

(\partial)/(\partial x)(-2y+2x)

\frac{\partial}{\partial x} (- 2 y + 2 x)

tangent of f(x)=(ln(x))^2,\at x=11 tangent of

f (x) = (ln (x))^{2}, at x = 11

integral from 0 to 2 of |x^2-sqrt(x)|

\int_{0}^{2} x^{2} - x d x

limit as x approaches 5 of 5x-(x-5)

x \to 5 lim (5 x - (x - 5))

Frequently Asked Questions (FAQ)

What is the solution for (x+2/y)dy+ydx=0 ?
The solution for (x+2/y)dy+ydx=0 is y=(2\W((xc_{1})/2))/(x)