What is the sum from n=1 to infinity of e^{-(9n)/2} ?

The sum from n=1 to infinity of e^{-(9n)/2} is converges

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sum from n=1 to infinity of e^{-(9n)/2}

n = 1 \sum \infty e^{- \frac{9 n}{2}}

converges

Solution steps

n = 1 \sum \infty e^{- \frac{9 n}{2}}

Apply Series Ratio Test:

converges

= converges

\int - 2 e^{- 2 x} sin (- 2 y)

f (x) = x^{4} + \frac{2}{x}

n = 0 \sum \infty \frac{n}{n ^{2} + 9}

f (x) = \frac{x ^{2} + 4}{x}

\frac{d}{d x} (\frac{x ^{3} - x ^{2} + 1}{x - 2})

What is the sum from n=1 to infinity of e^{-(9n)/2} ?
The sum from n=1 to infinity of e^{-(9n)/2} is converges