en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=x^2-6x+14

Solution

y^{^{'}} = x^{2} - 6 x + 14

Solution

y = \frac{x ^{3}}{3} - 3 x^{2} + 14 x + c_{1}

Solution steps

y^{'} (x) = x^{2} - 6 x + 14

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x^{2} - 6 x + 14 d x

\int x^{2} - 6 x + 14 d x = \frac{x ^{3}}{3} - 3 x^{2} + 14 x + c_{1}

y = \frac{x ^{3}}{3} - 3 x^{2} + 14 x + c_{1}

Graph

Popular Examples

\frac{d y}{d x} + 3 y = 4

y^{^{'}} = \frac{x + 1}{y}

limit as x approaches infinity of 3x+1/x

x \to \infty lim (3 x + \frac{1}{x})

integral of (2x-1)/(x^3-6x^2+11x-6)

\int \frac{2 x - 1}{x ^{3} - 6 x ^{2} + 11 x - 6} d x

limit as x approaches-infinity of-6/x

x \to - \infty lim (- \frac{6}{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=x^2-6x+14 ?
The solution for y^'=x^2-6x+14 is y=(x^3)/3-3x^2+14x+c_{1}