What is the derivative of 1/(6+x) ?

The derivative of 1/(6+x) is -1/((6+x)^2)

What is the first derivative of 1/(6+x) ?

The first derivative of 1/(6+x) is -1/((6+x)^2)

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\frac{d}{d x} (\frac{1}{6 + x})

- \frac{1}{( 6 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{6 + x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((6 + x)^{- 1})

Apply the chain rule:

- \frac{1}{( 6 + x ) ^{2}} \frac{d}{d x} (6 + x)

= - \frac{1}{( 6 + x ) ^{2}} \frac{d}{d x} (6 + x)

\frac{d}{d x} (6 + x) = 1

= - \frac{1}{( 6 + x ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( 6 + x ) ^{2}}

(1 + x^{2}) d y + (1 + y^{2}) d x = 0

\int (ln (x) - ln (x y)) d x

x \to \infty lim (i x)

\frac{d}{d x} (4 x^{3} - 5 x^{2} + 4 x - 1)

x \to - \infty lim (\frac{19}{20 + ( \frac{1}{x} )})

What is the derivative of 1/(6+x) ?
The derivative of 1/(6+x) is -1/((6+x)^2)
What is the first derivative of 1/(6+x) ?
The first derivative of 1/(6+x) is -1/((6+x)^2)