What is the solution for (dx}{dt}=\frac{4t)/x ?

The solution for (dx}{dt}=\frac{4t)/x is x=sqrt(4t^2+c_{1)},x=-sqrt(4t^2+c_{1)}

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(dx}{dt}=\frac{4t)/x

\frac{d x}{d t} = \frac{4 t}{x}

x = 4 t^{2} + c_{1}, x = - 4 t^{2} + c_{1}

Solution steps

\frac{d x}{d t} = \frac{4 t}{x}

Solve separable ODE:

x = 4 t^{2} + c_{1}, x = - 4 t^{2} + c_{1}

x = 4 t^{2} + c_{1}, x = - 4 t^{2} + c_{1}

f (x) = \frac{ln ( x )}{38 + x}

\int \frac{5 x ^{2} + 20 x + 6}{x ^{3} + 2 x ^{2} + x} d x

\int \frac{2}{x + 5} - cos (3 x) d x

\frac{8 x - 6}{x - 6}

y^{^{'}} - 4 y = 0.8

What is the solution for (dx}{dt}=\frac{4t)/x ?
The solution for (dx}{dt}=\frac{4t)/x is x=sqrt(4t^2+c_{1)},x=-sqrt(4t^2+c_{1)}