What is the integral of 1/(x(\sqrt[5]{x))} ?

The integral of 1/(x(\sqrt[5]{x))} is -5/(\sqrt[5]{x)}+C

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integral of 1/(x(\sqrt[5]{x))}

Solution steps

Simplify

= \int \frac{1}{x ^{\frac{6}{5}}} d x

Apply the Power Rule

Add a constant to the solution

\frac{d}{d x} (sin (2 x - 5) - 0.6 x)

y^{^{''}} + 3 y^{^{'}} + 2 y = 1

\int x e^{- 1} d x

\frac{d}{d x} (\frac{50 x}{1000 + 3 x})

\int e^{8 x + 1} d x

What is the integral of 1/(x(\sqrt[5]{x))} ?
The integral of 1/(x(\sqrt[5]{x))} is -5/(\sqrt[5]{x)}+C