What is the integral from 1 to 2 of integral from 0 to 0 of xye^{xy^2} ?

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integral from 1 to 2 of integral from 0 to 0 of xye^{xy^2}

\int_{1}^{2} \int_{0}^{0} x y e^{x y^{2}} d x d y

0

Solution steps

\int_{1}^{2} \int_{0}^{0} x y e^{x y^{2}} d x d y

\int_{0}^{0} x y e^{x y^{2}} d x = 0

= \int_{1}^{2} 0 d y

\int_{1}^{2} 0 d y = 0

= 0

\frac{\partial}{\partial x} (z)

- x^{3} + x^{2} + 16 x, 4 x, 0, 4

f (x) = (4 x + 5)^{4}, at x = - 1

n = 1 \sum \infty \frac{n}{3 n + 1}

\frac{\partial}{\partial x} (\frac{1}{x} cos (\frac{y}{x}))

What is the integral from 1 to 2 of integral from 0 to 0 of xye^{xy^2} ?
The integral from 1 to 2 of integral from 0 to 0 of xye^{xy^2} is 0