What is (\partial)/(\partial x)(e^xg) ?

The answer to (\partial)/(\partial x)(e^xg) is ge^x

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(\partial)/(\partial x)(e^xg)

\frac{\partial}{\partial x} (e^{x} g)

g e^{x}

Solution steps

\frac{\partial}{\partial x} (e^{x} g)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= g \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= g e^{x}

36 y^{^{''}} - 36 y^{^{'}} - 7 y = 0

x \to a lim (f (x))

\int e^{- t} sin (t) d t

\int (3 x^{2} + x - 2) d x

\frac{d}{d θ} (csc (θ))

What is (\partial)/(\partial x)(e^xg) ?
The answer to (\partial)/(\partial x)(e^xg) is ge^x