What is the limit as x approaches infinity of-2^x ?

The limit as x approaches infinity of-2^x is -infinity

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limit as x approaches infinity of-2^x

x \to \infty lim (- 2^{x})

- \infty

Solution steps

x \to \infty lim (- 2^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - x \to \infty lim (2^{x})

Apply the common limit:

x \to \infty lim (a^{x}) = \infty, a > 1

= - \infty

x ln (x) = y (1 + 15 + y^{2}) y^{^{'}} (x), y (1) = 1

\int e^{12 x} \cdot x^{3} d x

x \to - 4 lim (x^{3} - 4 x^{2} + 7)

3 y^{^{''}} - 12 y^{^{'}} + 9 y = 3 sin (4 x)

What is the limit as x approaches infinity of-2^x ?
The limit as x approaches infinity of-2^x is -infinity